python - 'str' object not callable -

i have problem in django:

'str' object not callable 

code:

urls.py app usuarios:

from django.conf.urls import patterns, include, url django.contrib.auth.views import login, logout_then_login usuarios.views import registro  urlpatterns = patterns('',     url(r'^login/$', 'django.contrib.auth.views.login', {'template_name':'registration/login.html'},                 name='login'),          url(r'^cerrar/$', 'django.contrib.auth.views.logout_then_login',          name='logout'),      url(r'^registro/$', 'registro', name='registro'), ) 

views.py

from django.http import httpresponse, httpresponseredirect django.contrib.auth import authenticate, login, logout django.core.context_processors import csrf  #importar el formulario de registro usuarios.forms import registrousuario   def registro(request):     if request.user.is_anonymous():         if request.method == 'post':         form = registrousuario(request, post)         if form.is_valid():                     form.save()             return httpresponse('usuario creado sin problemas.')             else:         form = registrousuario()         context = {}         context.update(csrf(request))         context['form'] = form         #pasar el context al template         return render_to_response('registro.html', context)     else:         return httpresponseredirect('/') 

forms.py:

from django import forms django.contrib.auth.models import user django.contrib.auth.forms import usercreationform   class registrousuario(usercreationform):     class meta:         fields = ('first_name', 'last_name', 'email', 'username', 'password1', 'password2') 

i not worked django , truth error not telling me might wrong.

environment:   request method: request url: http://127.0.0.1:8000/usuarios/registro/  django version: 1.6.2 python version: 2.7.6 installed applications: ('django.contrib.admin',  'django.contrib.auth',  'django.contrib.contenttypes',  'django.contrib.sessions',  'django.contrib.messages',  'django.contrib.staticfiles',  'usuarios') installed middleware: ('django.contrib.sessions.middleware.sessionmiddleware',  'django.middleware.common.commonmiddleware',  'django.middleware.csrf.csrfviewmiddleware',  'django.contrib.auth.middleware.authenticationmiddleware',  'django.contrib.messages.middleware.messagemiddleware',  'django.middleware.clickjacking.xframeoptionsmiddleware')   traceback: file "c:\python27\lib\site-packages\django\core\handlers\base.py" in get_response   114.                     response = wrapped_callback(request, *callback_args, **callback_kwargs)  exception type: typeerror @ /usuarios/registro/ exception value: 'str' object not callable 

you named view incorrectly in url dispatch:

from usuarios.views import registro  urlpatterns = patterns('',     # ...      url(r'^registro/$', 'registro', name='registro'), 

here 'registro' not name django can import (it not full module path), nor did specify prefix import (the first argument patterns() empty string '').

you should either give actual view object (that imported here), or give name full module path.

so pick 1 of:

from usuarios.views import registro  urlpatterns = patterns('',     # ...      url(r'^registro/$', registro, name='registro'), 

or

urlpatterns = patterns('',     # ...      url(r'^registro/$', 'usuarios.views.registro', name='registro'), 

the first option passes actual view function register (which works because imported already).

the second option gives full path module in addition view name; django can import (it looks . in string determine if can imported).