java - 'gomobile.user u' cannot be the first declaration of the FROM clause -

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i'm trying query data of user table in schema gomobile of derbydb.

i've established connection database , created jpa entity, columns corresponding database table.

@entity @table(name = "user", schema = "gomobile") public class user implements serializable {     private static final long serialversionuid = 1l;      // columns      public static list<user> getall() {         string querystring = "select u gomobile.user u";         entitymanager em = persistence.createentitymanagerfactory("eclipselink").createentitymanager();         return em.createquery(querystring, user.class).getresultlist();     } }

this stracktrace:

exception in thread "main" java.lang.illegalargumentexception: exception occurred while creating query in entitymanager:  exception description: problem compiling [select u gomobile.user u].  [14, 41] 'gomobile.user u' cannot first declaration of clause.     @ org.eclipse.persistence.internal.jpa.entitymanagerimpl.createquery(entitymanagerimpl.java:1605)     @ org.eclipse.persistence.internal.jpa.entitymanagerimpl.createquery(entitymanagerimpl.java:1625)     @ com.sap.sapchat.jpa.entities.user.getall(user.java:45)     @ com.sap.sapchat.jpa.entities.initdatabase.main(initdatabase.java:50) caused by: exception [eclipselink-0] (eclipse persistence services - 2.5.1.v20130918-f2b9fc5): org.eclipse.persistence.exceptions.jpqlexception exception description: problem compiling [select u gomobile.user u].  [14, 41] 'gomobile.user u' cannot first declaration of clause.     @ org.eclipse.persistence.internal.jpa.jpql.hermesparser.buildexception(hermesparser.java:155)     @ org.eclipse.persistence.internal.jpa.jpql.hermesparser.validate(hermesparser.java:347)     @ org.eclipse.persistence.internal.jpa.jpql.hermesparser.populatequeryimp(hermesparser.java:278)     @ org.eclipse.persistence.internal.jpa.jpql.hermesparser.buildquery(hermesparser.java:163)     @ org.eclipse.persistence.internal.jpa.ejbqueryimpl.buildejbqldatabasequery(ejbqueryimpl.java:142)     @ org.eclipse.persistence.internal.jpa.ejbqueryimpl.buildejbqldatabasequery(ejbqueryimpl.java:116)     @ org.eclipse.persistence.internal.jpa.ejbqueryimpl.<init>(ejbqueryimpl.java:102)     @ org.eclipse.persistence.internal.jpa.ejbqueryimpl.<init>(ejbqueryimpl.java:86)     @ org.eclipse.persistence.internal.jpa.entitymanagerimpl.createquery(entitymanagerimpl.java:1603)     ... 3 more

my persistence declaration in persistence.xml looks this:

<persistence-unit name="eclipselink" transaction-type="resource_local">     <class>jpa.entities.user</class>     <properties>         <property name="javax.persistence.jdbc.url" value="jdbc:derby://localhost:1527/gomobile;create=true" />         <property name="javax.persistence.jdbc.user" value="gomobile" />         <property name="javax.persistence.jdbc.password" value="mypassword" />         <property name="javax.persistence.jdbc.driver" value="org.apache.derby.jdbc.clientdriver" />     </properties> </persistence-unit>

edit

if use:

string querystring = "select * gomobile.user u";

i error:

exception in thread "main" java.lang.illegalargumentexception: exception occurred while creating query in entitymanager:  exception description: syntax error parsing [select * gomobile.user u].  [38, 38] select statement must have clause. [7, 7] left expression missing arithmetic expression. [9, 38] right expression not arithmetic expression.     @ org.eclipse.persistence.internal.jpa.entitymanagerimpl.createquery(entitymanagerimpl.java:1605)     @ org.eclipse.persistence.internal.jpa.entitymanagerimpl.createquery(entitymanagerimpl.java:1625)     @ com.sap.sapchat.jpa.entities.user.getall(user.java:75)     @ com.sap.sapchat.jpa.entities.initdatabase.main(initdatabase.java:64) caused by: exception [eclipselink-0] (eclipse persistence services - 2.5.1.v20130918-f2b9fc5): org.eclipse.persistence.exceptions.jpqlexception exception description: syntax error parsing [select * gomobile.user u].  [38, 38] select statement must have clause. [7, 7] left expression missing arithmetic expression. [9, 38] right expression not arithmetic expression.     @ org.eclipse.persistence.internal.jpa.jpql.hermesparser.buildexception(hermesparser.java:155)     @ org.eclipse.persistence.internal.jpa.jpql.hermesparser.validate(hermesparser.java:334)     @ org.eclipse.persistence.internal.jpa.jpql.hermesparser.populatequeryimp(hermesparser.java:278)     @ org.eclipse.persistence.internal.jpa.jpql.hermesparser.buildquery(hermesparser.java:163)     @ org.eclipse.persistence.internal.jpa.ejbqueryimpl.buildejbqldatabasequery(ejbqueryimpl.java:142)     @ org.eclipse.persistence.internal.jpa.ejbqueryimpl.buildejbqldatabasequery(ejbqueryimpl.java:116)     @ org.eclipse.persistence.internal.jpa.ejbqueryimpl.<init>(ejbqueryimpl.java:102)     @ org.eclipse.persistence.internal.jpa.ejbqueryimpl.<init>(ejbqueryimpl.java:86)     @ org.eclipse.persistence.internal.jpa.entitymanagerimpl.createquery(entitymanagerimpl.java:1603)     ... 3 more

there no entity called gomobile.user, cannot use in jpql queries. jpql object based, , not use tables/schema , fields directly in sql.

you should using "select u user u", entity quering named "user" default.


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