bash - read a list of IP address and execute commands depending on OS type -

i working on script read file having multiple ip addresses, login each system (no ssh keys involved , manually entering password), execute command depending on os type , print result.

here how ips defined in hosts.txt file

#~] cat hosts.txt  10.6.3.131  10.6.3.132  10.6.3.11  10.6.3.12 

when execute below script, following errors shown. also, script not prompt 2nd , rest ips in list. causing this?

# ./hq-test1.sh  root@10.6.3.131's password:  awk: cmd. line:1: nr==1{print  awk: cmd. line:1:            ^ unexpected newline or end of string  bash: line 2: [: !=: unary operator expected  10.6.3.131 == pass 

this script used in test :

#!/bin/bash  while read host;    if ssh root@$host '        status=`awk 'nr==1{print $1}' /etc/*release`        [ $status != "centos" ]     ';         echo "$host == fail"    else         echo "$host == pass"    fi  done < hosts.txt 

your script isn't closing stdin while running ssh command first host of list processed.

i simplified test, awk able check os name , temporary variable unnecessary.

while read host;   if ssh -n root@$host '[ "$(awk "/centos/{print}" /etc/*release)" ] '          echo "$host == pass"   else        echo "$host == fail"   fi done < hosts.txt