java - How to get selected row values in easygrid -

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i create custom button "open" in grails easygrid plugin. want parameters in button. how can values selected row?

<grid:grid id='jqgridinitial' name='customerlist' jqgrid.caption="'customer'"        open="${g.createlink(controller: 'customer', action: 'index', params:[???] }"

this javascript code return selected row:

var row = jquery("#jqgridinitial_table").jqgrid('getgridparam','selrow');

but, think need custom jqgrid formatter: http://www.trirand.com/jqgridwiki/doku.php?id=wiki:custom_formatter

you can see example here: https://github.com/tudor-malene/easygrid_example/blob/master/grails-app/views/author/_jqgrid.gsp

and here how works ( click on author name , links wikipedia): 199.231.186.169:8080/easygrid/author/list?impl=jqgrid

in case should construct link customer based on actual row data


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