Java http request client example -

i new in computer networking , have exercise create java http client example.

the exercise instruction:

socket soc = new socket(host, port);  datainputstream in = new datainputstream(soc.getinputstream()); bufferedwriter out= new bufferedwriter(new  outputstreamwriter(soc.getoutputstream()));   out.write(httprequest); out.flush();  string httpresponse= in.readutf(); 

and code:

import java.io.bufferedwriter; import java.io.datainputstream; import java.io.ioexception; import java.io.outputstreamwriter; import java.net.socket; import java.net.unknownhostexception;   public class mytest{     public static void main(string[] args) throws unknownhostexception, ioexception{          string host = "gg.gg";         string httprequest = "get / http/1.1 host:gg.gg ";         int port = 80;          socket soc = new socket(host, port);           datainputstream in = new datainputstream(soc.getinputstream());         bufferedwriter out= new bufferedwriter(new          outputstreamwriter(soc.getoutputstream()));            out.write(httprequest);         out.flush();           string httpresponse = in.readutf();          system.out.println(httpresponse);         //soc.close();     } } 

but when run program, run long time, , found readutf() method. run 20s display message:

does request "get / http/1.1 host:gg.gg " not correct, or error here? want use instruction form, not solution. thanks! (i'm not @ english much)

• an http 'end of line marker' cr lf or \r\n.
• the 'simple request' format simple-request = "get" sp request-uri crlf

you should do:

string httprequest = "get /\r\n"; 

in addition, in.readutf() uses 'modified utf-8' , not want, expects size of string specified first 2 bytes.

while not efficient, works:

int read;  while ((read = in.read()) != -1) {   system.out.print((char) read); } 

(this ignores encoding response is, happens come utf-8 , that's fine casting (char). proper encoding handling out of scope answer.)