java - Map a Stream<T> to a Map<T, Long> that is counting? -

i have stream<t>, possible generate map<t, long> increases count 1 every element? i'd if reverse t, long long, t, before storing in map, example input/output:

example contents of stream<string>:

kgj def dgh 

wanted output first question:

(kgj, 1) (def, 2) (dgh, 3) 

wanted output in end:

(1, kgj) (2, def) (3, dgh) 

what have far, stream<vertexdata>:

    primitives.stream()             .flatmap(primitive -> primitive.getvertexdata().stream())             .distinct()             .collect(collectors.groupingby(i -> i, collectors.counting()))             .foreach((k, v) -> system.out.println("k = " + k + " / v = " + v)); 

this turns stream<primitive> stream<vertexdata> distinct elements, , map<vertexdata, long> counts occurences, not want, want keep on counting @ every element passes.

is there way ask?

what can write own collector counting on elements encountered. following works:

  stream<string> strings = stream.of("kgj", "def", "dgh");    strings.distinct().collect(collector.of(           hashmap::new,           (biconsumer<map<string, long>, string>) (map, str) -> {             map.put(str, long.valueof(map.size() + 1));           },           (left, right) -> {             long s = left.size();             right.entryset().foreach(e -> left.put(e.getkey(),                                                    long.valueof(                                                            e.getvalue()                                                                    .longvalue()                                                            + s)));             return left;           })).foreach((k, v) -> system.out.println("k = " + k + " / v = " + v)); 

note (somewhat complex) combiner (third argument collector.of() needed in cases stream processed in parallel).